view at statistics

[winkel]

Hi tucktuckster,

interesting thoughts you have. But it´s much to early for that.

What you see is the theoretical average.
To build a system on it would fail, because this average appears only at about 20 percent of all games!
If you add "Sigma" to it it´s only about 40-41%.

look at this:

the normal way to count numbers which appeard/not appeared and theirs percentage:

Code Select Expand


app      not      %      count
37      0            
36      1            
35      2            
34      3            
33      4      0,00      2
32      5      0,00      55
31      6      0,01      642
30      7      0,06      5242
29      8      0,33      29123
28      9      1,37      120524
27      10      4,14      363630
26      11      9,34      819843
25      12      15,82      1388424
24      13      20,32      1782993
23      14      19,88      1744741
22      15      14,83      1301553
21      16      8,47      743249
20      17      3,70      324510
19      18      1,23      108113
18      19      0,34      29475
17      20      0,09      7947
16      21      0,04      3501
15      22      0,02      1658
14      23      0,01      633
13      24      0,00      204
12      25      0,00      16
11      26            
10      27            


or as a diagram

[Herb]

Again, what is it that you think you can do with this information?

[winkel]

Again, what is it that you think you can do with this information?

If you are not able to follow a line of arguments to it's end, then stop reading.
If you can't get any information out of this, then stop reading.
You mustn't read this at all.
It is only what we call basics.
I didn't never ever talk about a system nor using it to win.

[winkel]

The above listed statistic origins of 8776078 full rotations of 37 spins.
That means 324 714 886 consecutive single spins.

I don't know any other statistic made from such an amount of spins.

The so called Law of third is describing:
After 37 spins there are
24 numbers appeared
12 of them repeated
that misleads all who believe this and try make a system out of it.

The truth is:
after 37 spins there are
24 numbers appeared
10 of them repeated (F)
14 number appeard once (N)
13 numbers didn´t appear (R)

so let´s have a closer look to the point where there are 13 R (24 appeared)
Do we have always 10F and 14N at this point? NO!

[winkel]

As we can see also this distribution is following the rules of statics. The so calle bell of Gauss is conformed.

When we play one number we have a 1/37 possibility to win.
Would we rely on the law of third and try to play 13 Number we have a chance of 13/37 against 24/37

Referring to the above list we have now a new view:

Our Chance is still 13/37 if we play R
But we have a new description of our Odds:
e.g. there could be: 13 16 08
if we bet on R 13/37
if we bet on N 16/37
if we bet on F 8/37

But how can we decide which is to play?

We will have to have a closer look.

BR
winkel

[Tucktuckster]

well here is an interesting one.

step 1 - track 37 spins. record all sleepers, ie no hits.

step 2 - track next 37 spins. record all of the above sleepers that hit just once in the 37 spins.

step 3 - play the numbers that were recorded in step 2. average around 5 or 6.

based on my testing - the end result is that the negative expectancy is reversed. it doesnt always win. sometimes can be not great, but in long run it seems to work. i ran it through over 7000 possible sequences. but my testing could be wrong.

a possible option would be to play to first winner with a mild progression. or play to first profit with a mild progression.

[winkel]

Hi tuck,

one question that will answer your idea:

if we have 74 spins, how many rotations with 37 spins do we have then?

br
winkel

[Tucktuckster]

now that depends on your view on a 37 spin cycle.

in theory you could have 2 - namely spins 1-37 & 38-74.

alternatively you could have 38, being spins 1-37, 2-38, 3-39 and so on.

depends on definitions.

i actually revisited my testing and there was an error on the code. i am starting to run into dead ends with some of my testing here. i am 99% sure that there is a system waiting to be used, but basically playing on spreadsheets isnt really any fun and im not getting anywhere on this,

[winkel]

Hi Tuck

my English seems to be so bad, that nobody understands, that I'm talking about basics. I'm not talking about the way to use these statistics for a bet-selection.

br
winkel

[ernesto]

.

ernesto

[TwoCatSam]

Ernesto

Brother, I can't answer your question; not sure I even saw it, but I have one of my own.

You start with 37 unhit numbers and move toward 37 hit numbers, is that correct?  What is the large bulge at spin 23 or so?  I have seen this graph many times over the years and no one has ever explained it on my level.

Any help from anyone would be nice.

Sam

[Shorty]

Sam.
I'm not sure if this is correct as I haven't seen it before, but my guess is this:

23 means that 23 numbers have hit and 14 have remained unhit, in the 37 spin cycle.

So therefore 19.88% of the time there will be 14 unhit numbers after 37 spins.

It peaks at 24 which is 13 unhit numbers. So 24 numbers in 37 spins - law of thirds.

[TwoCatSam]

33      4      0,00      2
32      5      0,00      55
31      6      0,01      642
30      7      0,06      5242
29      8      0,33      29123
28      9      1,37      120524
27      10      4,14      363630
26      11      9,34      819843
25      12      15,82      1388424
24      13      20,32      1782993.......Shorty, I'm talking about the 1782993.  What is that?
23      14      19,88      1744741
22      15      14,83      1301553
21      16      8,47      743249
20      17      3,70      324510
19      18      1,23      108113
18      19      0,34      29475
17      20      0,09      7947
16      21      0,04      3501
15      22      0,02      1658
14      23      0,01      633
13      24      0,00      204
12      25      0,00      16
11      26           

[ernesto]

Sam

If we add all in the last column we get ~ 8.776.078. We have more than 8 million 37 spin cycle.
From this 8 million, we have 1.782.993 cycle where we can found exactly 24 number different number from the 37 spins.
This is the most frequent.

ernesto

[Shorty]

^^ Yup, that's what I assumed.

[Shorty]

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