The 4Selecta system

[TwoCatSam]

Mr. Tuckster

Mr. Chips is very good at teaching.  Words are tricky things to use to convey meaning.  So much easier to teach in person.

I have put nearly two weeks into working on this system and fighting Wild Jack Casino at the same time.  I do feel he's onto something or I wouldn't continue to work at it.

Welcome to the fray!!  Now we are three.

Sam

[Tucktuckster]

right then - here goes session. my latest from weekend. was 84 spins.

6 = root group 6 in MG.
1 = in Lower group.

so next number should give us a group.

10 = Lower group.

So

LG = 1  MG = 0 HG = 0 C = 0

10

next one out is 24= MG,
next one is 22 = MG,

we need 2 groups to look for a possible so we march on and 24+22 = just 1 group

next one is 20 which is a LG.

so now we have 1 lg and 1mg (24 and 22 count as one)

so the 7th number will form the set. we have only had a LG and we could get another - so our only bet is to go with number 10.

the 7th number is number 2. A LG number but not our punt.

therefore we are -1 in the p&l and the scorecard looks as follows

LG = 2,   MG =0,   HG = 0,   C= 0
10,2,

So LG is only active group and is winning.

the 8th number will be start of a new group.

[Tucktuckster]

8th spin = 35 HG
9th spins = 4 MG

So we cannot nail a LG which is dominant and in lead. this is where i wish i had read more. do we play the LG numbers to look for a C or do we accept there is no bet and let the group conclude. since the C may be sleeping - I leave to conclude, but await guidance.

10 spin is 31 or MG. So MG is now active but LG dominant.

LG=2, MG=1, HG =0, C=0
10,2     31 

31 = MG,
36 = HG,

So we have no chance of a leader however the MG is now our active group and there is a chance of a MG so will bet number 31.

13th spin is number 33. A loser but MG.

so p&l is now -2

LG =2    MG = 2   HG =0    C=0
10,2       31,33

14th spins is 22 MG
15th = 35 or HG.

MG is now joint leader and is also the active one - so we punt on 31 & 33.

16th spin is the number 5.

Another MG but wrong number.

we lose 2units and p&l is now -4.

MG in lead with 3 and active numbers = 31,33 and 5.

17th spin = 23 MG
18th spin = 18 = HG
so again MG is option and we punt our 3 numbers above.

19th spin is 11 or LG. we have our first C and lose 3u so p&l is -7

how am i doing thus far (awaits some smart person to say i am 7u down).......

[Tucktuckster]

20th spin =32 MG,
21st spin = 4 MG so these two count as one
22nd spin = 18 or HG.

Mmmmm. Leader group is MG with 3 so that gets the nod ahead of active group (i think this is right) which would be C.

MG numbers are 5,31,33

spin 23 is 2. so we lose -3. we now have -10 in p&l.

C     &    LG = 2       MG = 3     HG = 0

2,11       10,2           31,33,5

Now this is where i go to re-read instructions. Did i do the right thing by keeping the 11 in the C section. something says that i should have put in LG numbers section.

The reason why i want to check is that if i had done this and if i had bet the active section rather then higher instance section, then i would have bet 10,2,11 and i would have won.

next spin will be 24 but im off to re-read (I hate reading!)

[Tucktuckster]

right - as thought the C number goes in relevant section, but luckily for me - the bet was right.

so spin 24 it is and we are -10.

s24 = 33,
s25 = 33,
s26 =6 (would be nice for followers of the system that says when a rg hit in 2 spins, back it in next one.....)
spin 27 = 19. so we have a MG and we have a LG.

MG is our leader with 3 and so we have 3 numbers, 33, 31 and 5.

spin 28 is number 27. a HG and our next C. C now has 3 and is joint leader but active. HG has a number at last. p&l -13.

spin 29 is number 5
spin 30 is number 29. so we have MG and a LG. C is our leader so we want a HG which means our lone number 27 is the one we bet on.

spin 31 is number 18. so hg but wrong number. so p&l is -14. Doing okay thus far for not hurting the old bank too much. 18 added to HG numbers.

spin 32 = 2, spin 33 = 13. here we are hunting a C and we have 18 and 27 as our weapons of choice....

spin 34 = 22. Another loser and we have a MG. P&L is -16.

I'll recap my tally so i dont forget.

C = 4     MG = 4 and active   LG = 2  and HG = still on a big fat zero.

numbers

31,33,5,22                   10 {2} 11            18, 27

note brackets around the 2 to signify that it has landed twice.

spin 35 is next up.

[TwoCatSam]

tuck

This is not a criticism, but I have grown accustomed to seeing things as Mr. Chips originally posted and I can't read your post very easily.

1LG
36HG

That is how he does it.

Two definitions:  The Table is where you note which Section is at what number or whether or not they are "last active".

LG   MG    HG    CG
1              1.
2
3

If this were a brand new trot, HG would trump LG as it is "last active".  Later, at spin #3,  LG takes the lead.

Next definition:

The Numbers Group.  I tried to call it "The Hat" but Mr. Chips would have none of it.  A stickler, he is!

LG    MG   HG
1
[1]

If the third number makes a CG:

LG
MG
HG

the number for HG goes under HG.

HG
MG
LG

Now goes under LG

LG
HG
MG

Now goes under MG

Sam

[Tucktuckster]

I have no idea whether this system will work or not by the way.

Just doing my share of testing since its always the same old souls that do it......

so spin 35 was 8, 36 was 5

we have a HG and a MG so we want a MG as our active leader and its a 17 for spin 37. boo hiss.

That gives us a HG and they are off the mark. we lose another 4, so -20.

spin 38 is 10, spin 39 is 19, spin 40 is 23. we have lg & mg so we want a mg since is joint leader last active. 4 numbers to bet on and spin 41 is 15. A middle group number but not one of ours. we move to -24.

spin 42 is 2, spin 43 is 13. again we are hunting mg since took lead with last hit to be 5 instances. we now have 5 numbers to stake on. spin 44 is 18. a hg number. we are now -25.

calling it a night tonight as i have heaps of work tomorrow. i will continue this though. would be good to get confirmation i am testing right.

scorecard as follows:

MG & C = 5 a piece    LG =2     and HG =1

31,33,5,22,15             10 (2) 11      (18),27,17

we will start with C as our active joint leader and next spin is 45. pl = -25

[TwoCatSam]

tuck

I don't know either.  Will it work or not?  We'll find out.

Sam

[Tucktuckster]

sam - if i read you right, i will revisit my format.

i also have the last active wrong. the last active = the last active number drawn from the wheel and not the last active group to land.

so as an example
1 LG
4 MG
6 Mg
-------
2LG
5MG
1LG
--------
Both the LG and MG have 1 win each. i took last active to be the LG from this point.

What you are saying is that Last active is decided by Last active number.

so next number as follows

8 HG
5MG = Last active number drawn is middle group and not LG which was my error. hence we now bet the MG. Is this correct.

[Natural9]

Ugh my mind must be slow still trouble picking this up Brain box hurts

So what was your result Tuck

[TwoCatSam]

tuck

Before we even ask about "last active", we must look at the Table......

LG   MG    HG    CG
1              1.
2
3

We see the Lg Section is in the lead.  No more to say....unless....you had this:

MG
HG

Since there is no Lg in the "Potential Section", we look back to who was "last active" and we see the HG was, although it was a couple of spins back.  Since we do have an HG in our Potential Section, we can bet the numbers we have in our Number Group under HG.

Sam

[TwoCatSam]

9

You'll get it!

Sam

[Mr Chips]

I am sure there is still a problem with the 'active' Group section. I went back to the explanation I gave on page 1 in case I slipped up somewhere in explaining it.
 
I think I explained the 'active' Group section applies (perhaps I should have stipulated ONLY APPLIES) when two or more Group sections are equal e.g
 
LG   MG   HG   C
1      1     1    1
2      2     2.
 
LG, MG, HG are equal, but HG is the 'active Group section and therefore the betting will be on available HG numbers.
 
This is the only time the 'active' applies in the Table.
 
Bets will always go on the leader and if no leader then when two or more Group sections are equal the 'active' applies.
 
tucktuckster,
 
Congratulations you have a reasonable grasp of the system, I will reply in detail to your posts very soon.
 
Mr Chips
 

 

[Natural9]

Yes Sam one day

And also if it works why does it because A method needs something differant or special  for it  to over come the  casino edge  

[TwoCatSam]

9

I think I've said enough.  Mr. Chips is back and he should answer that question.

I will only speak of things I am 99.9% sure of.

Sam

[TwoCatSam]

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