How to find a consistent bet the Enrique way.

[NoBody]

To all,

Ok. Let's understand what is the numbers are.

There are 3 numbers.

Example:

16. 2A, --, --
30. 3C, 3A, 2B

Ok...

So, the first spin is 16.
2= 2nd Dozen (actual dozen in the roulette table layout)
A= 1st Column (actual column in the roulette table layout)

Because there are no previous spin, so the 2nd and 3rd number is --.

So, the second spin is 30.
3= Third Dozen (actual dozen in the roulette table layout)
C= Third Column (actual column in the roulette table layout)

3A is the result from the Wheel 1.
Looking at the first wheel.(on reply#77) The arrow is pointing at 16.

We are looking for 30 (at the outside disc)
30 is at 3rd Dozen of Wheel 1.
30 is also at A of Wheel 1.
So it is 3A.

2B is the result from the Wheel 2.
Looking at the 2nd wheel (on reply#77)

We are looking for 30 (at the outside disc of Wheel 2)
30 is at 2nd Dozen of Wheel 2.
30 is also at B of Wheel 2.
So it is 2B.

So, 30 = 3C, 3A, 2B

Understand???

It is not that difficult to find the figure.

In fact, at reply #53 TTT has came out with a full graph. It is much easier to find the figure with the graph. But take note that the figure is showing result of wheel 2 then wheel 1.
So, the result of 16-->30 is 2b3a.

However we are still waiting for Enrique to teach us how to use this info.

Regards,
Nobody ^.^

[TwoCatSam]

If I understand it--and don't hold me to this--you look for something missing from each of the three columns.  When you have something from each, you take the table layout and cross off all the numbers except the three things you have.  Say you have 1C 3B and 2A.  Mark off all those numbers from the chart and what you have left is your bet.

What I don't understand is how far back you go in the spun numbers.  Do you look at three, four, five or does it matter.  As long as the above conditions are met, you have a bet.  I would think the last three spins would be the most logical answer.  You want a "misser" in each column in the last three spins.

Just postulating; not for certain!

Sam

[JHM]

Enrique,

How are you doing with the chart?

Lot of us lookig forward to see it I think 

[JLP]

If I understand it--and don't hold me to this--you look for something missing from each of the three columns.  When you have something from each, you take the table layout and cross off all the numbers except the three things you have.  Say you have 1C 3B and 2A.  Mark off all those numbers from the chart and what you have left is your bet.

What I don't understand is how far back you go in the spun numbers.  Do you look at three, four, five or does it matter.  As long as the above conditions are met, you have a bet.  I would think the last three spins would be the most logical answer.  You want a "misser" in each column in the last three spins.

Just postulating; not for certain!

Sam

Hey Sam,
You answered it yourself.

On Post #31 Enrique says the following :

As for how many previous spins do you look back?  I use a minimum of 2/3. I want to try and catch a good run early if I can.

Cheers,
JLP.-

[TwoCatSam]

JLP.-

But what would one do after a win?  Scratch off the older spins?  Maybe this would become clear once a person is doing it.

Thanks!

Sam

[TwoCatSam]

From each of our three colums:

1A  2B  3C........just an example.

Do we want to find only one group missing in each three.  I mean, what if 2A is missing from one column instead of just 2 or A?

I am totally unclear on the "rules" or I would be testing.

Sam

[JLP]

From each of our three colums:

1A  2B  3C........just an example.

Do we want to find only one group missing in each three.YES  I mean, what if 2A is missing from one column instead of just 2 or A?

I am totally unclear on the "rules" or I would be testing.

Sam

If we have the following example on 3 spins :

1A  2B  3C
2B  3A  3C
2C  1B  3B

In the 1st one looking vertical the 3 dozen is missing (we can use this) but the three ABC columns are present (we cannot use it).

In the second set looking vertical the 3 dozens are present (we cannot use this), but misses C in the columns(we can use it).

In the 3rd. set looking vertical we have the same dozen 3 (we cannot use this), but we have A missed in the columns (we can use this).

That is how I understand it.

Cheers,
JLP.-

[TwoCatSam]

JLP.-

What if we took your chart and changed it.  Me in blue.

3B   2B  3C
2B  3A  3C
2C  1B  3B

Now in the first column, you have both 1 and A missing.  My question is this:  Must you have only one item missing from a column, or may there be two?  I am defining "column" as being 1A or 2B....not 1 by itself or B by itself.

Sam

[TwoCatSam]

Real numbers:

[table=,]
Spun,,,Real,,,Clear,,,Red
19
33,,,3C,,,2B,,,2A
3,,,1C,,,1A,,,2A
2,,,1B,,,3C,,,1B
[/table]

From the Real column, you have 2A missing.  (Real is what 33 is on the table.)
From the Clear wheel column, you have nothing missing.
From the Red wheel column, you have 1,3 and B,C missing.

Where do we go from there?

Sam

[TwoCatSam]

Has anyone noticed this:

17. 2B, (THIS IS DOZEN AND COLUMN) 1C,   3C.
--
28. 3A,   2C,   1B.
--
15. 2C,   1A,   2C.
--
24. 2C,   2C,   1C.
--
35. 3B,   2B,   1B.
--
16. 2A,   2C.   2C.
--
In the first section going down of dozen and column, the first dozen is missing.
In the second section going down of dozen and column, the 3rd dozen is missing.
In the third section going down of dozen and column, the first column is missing.

So from the number 17 you can discount all of the 1st dozen=1,2,3,4,5,6,7,8,9,10,11,12.
You can also discount from the second section all of the 3rd dozen=12,35,3,26,0,32,15,19,4,21,2,25.
you can also discount from the third section all of the A column=18,21,24,27,30,33,36,2,5,8,11,14.

Now that only leaves these numbers left to back=13,16,17,20,22,23,28,29,31,34. (10 numbers in all)

The winning number was 28. You have 36 chips.  END OF ENRIQUE'S POST.

Me now........

Look at the red.  Why do we care if it was 2B?  We would not use that 2B in our calculations, would we?

Look at the navy blue.  The 28 is the second number in the trot, but look at the maroon.  How could 28 have figured into the calculations and then be a winning number?

If anyone is going to take this system seriously, we need some hard-and-fast rules or at least some explanation.

Sam

[JLP]

JLP.-

What if we took your chart and changed it.  Me in blue.

3B   2B  3C
2B  3A  3C
2C  1B  3B

Now in the first column, you have both 1 and A missing.  My question is this:  Must you have only one item missing from a column, or may there be two?  I am defining "column" as being 1A or 2B....not 1 by itself or B by itself.

Sam

Hi mate,
It can be two items on a certain column, that is possible so their corresponding numbers would be discarded.

Read here on post #33 Enrique´s example :

26=3B.
02=1B,   1A,   2A.
14=2B,   2A,   1C.
15=2C,   2B,   1A.

In the 1st group there is no 3rd dozen and no column A.

In the 2nd group there is no 3rd dozen and no column C.

In the 3rd group there is no 3rd dozen and no column B.

After working out the calculations, the only numbers I would bet on would be 2 and 15.

The next number was

02=1B,   1A,   2C.

So for a 2 chip bet, I would get back 36 chips.

Cheers,
JLP.-

[JLP]

Real numbers:

[table=,]
Spun,,,Real,,,Clear,,,Red
19
33,,,3C,,,2B,,,2A
3,,,1C,,,1A,,,2A
2,,,1B,,,3C,,,1B
[/table]

From the Real column, you have 2A missing.  (Real is what 33 is on the table.)
From the Clear wheel column, you have nothing missing.
From the Red wheel column, you have 1,3 and B,C missing.

Where do we go from there?

Sam

From the Real column, you have 2A missing.  (Real is what 33 is on the table.)
So we discard all numbers from 2nd. dozen (13 to 24) and all numbers from 1st column 1 to 34 on the table layout.

From the Clear wheel column, you have nothing missing.
This we not use, so nothing is discarded.

From the Red wheel column, you have 1,3 and B,C missing.
No, you have 3 and C missing.
So we discard all this numbers from its relative position in the second disc in relation to the last number spun. That I have yet to see (haven´t constructed the 2 wheel set yet).

Cheers,
JLP.-

[JLP]

Has anyone noticed this:

17. 2B, (THIS IS DOZEN AND COLUMN) 1C,   3C.
--
28. 3A,   2C,   1B.
--
15. 2C,   1A,   2C.
--
24. 2C,   2C,   1C.
--
35. 3B,   2B,   1B.
--
16. 2A,   2C.   2C.
--
In the first section going down of dozen and column, the first dozen is missing.
In the second section going down of dozen and column, the 3rd dozen is missing.
In the third section going down of dozen and column, the first column is missing.

So from the number 17 you can discount all of the 1st dozen=1,2,3,4,5,6,7,8,9,10,11,12.
You can also discount from the second section all of the 3rd dozen=12,35,3,26,0,32,15,19,4,21,2,25.
you can also discount from the third section all of the A column=18,21,24,27,30,33,36,2,5,8,11,14.

Now that only leaves these numbers left to back=13,16,17,20,22,23,28,29,31,34. (10 numbers in all)

The winning number was 28. You have 36 chips.  END OF ENRIQUE'S POST.

Me now........

Look at the red.  Why do we care if it was 2B?  We would not use that 2B in our calculations, would we?

Look at the navy blue.  The 28 is the second number in the trot, but look at the maroon.  How could 28 have figured into the calculations and then be a winning number?

If anyone is going to take this system seriously, we need some hard-and-fast rules or at least some explanation.

Sam

Hi Sam,

Yes that is true what you say, I agree.He is talking of numbers that have not spun yet.
Maybe Enrique not explain clearly the process.
But I think the 17 is not the first number from where he begins the calculations, I think this is a sequence where there are others numbers previous to 17 (so the 3 items appears in its line).

Cheers,
JLP.-

[TwoCatSam]

JLP.-

I made a serious mistake there, didn't I? 

Guess I better try this on paper and see if I can figure it out.  Thanks for all your explanation.

Sam

[TwoCatSam]

All.........

Well I took my printout to bed and studied it.  We have the "real" columns and dozens as we've always known them and then we have enrique's columns and dozens as he describes them with his wheels.  They are not the same.  I guess everyone figured that out except Sammy Slowbrain.

Sam

[TwoCatSam]

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